8086 assembly language program to display current date 
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Murugan Andezuthu Dharmaratnam | 
08 September 2020 | 
8279
08 September 2020 | 8279
A couple of months back someone had sent me a message on Facebook to help him write an assembly language program to display the current date. He was a beginner in 8086 and wanted the code at the earliest. I spend some time and quickly wrote this sample code. It could have been written in a much better way or even in a much simpler way, But this is the code I came up with at that time.
first, let me show you the code, and then I will give a detailed explanation.
8086 code to display the date
.model tiny
.code
org 100h
main proc near
mov ah,2ah
int 21h
push dx
mov ax,cx
mov si,offset year
call hexToAsc
pop dx
push dx
mov ah,00
mov al,dh
mov si,offset month
call hexToAsc
pop dx
push dx
mov ah,00
mov al,dl
mov si,offset day
call hexToAsc
pop dx
mov ah,09h
mov dx,offset messagecurrentdate
int 21h
mov ah,4ch
mov al,00
int 21h
messagecurrentdate db 0ah,0dh,"Current Date : "
day db ' '
separator1 db '/'
month db ' '
separator2 db '/'
year db " $"
endp
hexToAsc proc near ;AX input , si point result storage addres
mov cx,00h
mov bx,0ah
hexloop1:
mov dx,0
div bx
add dl,'0'
push dx
inc cx
cmp ax,0ah
jge hexloop1
add al,'0'
mov [si],al
hexloop2:
pop ax
inc si
mov [si],al
loop hexloop2
ret
endp
end main
Output
I am using emu8086 to run the code
Code explained in detail
Since this is 4beginner and since I know it's going to be students who are going to search for this code. I will break down the code into pieces and explain it step by step.